Points P and Q are tries toom points on segment AB. If AQ =7x+6 and PQ= 3x+5, find all possible values for the length of AB.
So far I've established that 4x+1 is the length of AP and QB
So the total length of AB should be 11x+7 I think, I'm not sure how to solve and find the values
what the heck are tries toom points ?
If this is the old trisection problem, then you know that
AQ = 2 PQ, so
7x+6 = 2(3x+5)
7x+6 = 6x+10
x = 4
PQ = 17
Now, AB = 3 PQ = 51