# Calculus

Differentiate.
cos^-1 2x

1. is this arccos (2x)?

or do you mean 1/(cos 2x)

posted by bobpursley
2. I think we can assume arccos.

If so, then recall that d/dx (arccos(u)) = -1/√(1-u^2) du/dx

Now just plug and chug.

posted by Steve

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