In the reaction between bromine and sodium, a bromine atom gains an electron. What ion is formed? Is the bromine oxidized, or is it reduced?
In the reaction between bromine and sodium, a bromine atom gains an electron and forms the bromide ion, Br–. What happens to bromine?
In the reaction between bromine and sodium, a bromine atom gains an electron and forms the bromide ion, Br–.
What happens to bromine?
Thank you DrBob222!!!!!
To determine the ion formed in the reaction between bromine and sodium, as well as whether bromine is oxidized or reduced, we need to understand the concept of oxidation and reduction.
Oxidation and reduction are terms used to describe the transfer of electrons between atoms or molecules. In a reaction, if an atom or ion loses electrons, it is oxidized, while if it gains electrons, it is reduced.
In the case of the reaction between bromine and sodium:
Bromine is a halogen element and its electron configuration is 1s²2s²2p⁶3s²3p⁶4s²3d¹⁰4p⁵.
Sodium is an alkali metal and its electron configuration is 1s²2s²2p⁶3s¹.
During the reaction, sodium donates its one valence electron (3s¹) to bromine. This electron is transferred from sodium to bromine.
As a result, the bromine atom gains an electron and becomes an anion (a negatively charged ion). When bromine gains one electron, its electron configuration becomes 1s²2s²2p⁶3s²3p⁶4s²3d¹⁰4p⁶, just like the noble gas krypton (Kr). Therefore, the bromine atom forms the bromide ion (Br⁻).
Now let's determine whether bromine is oxidized or reduced:
Since the bromine atom gains an electron, it has a reduction in its oxidation state (the number of electrons lost or gained). In its elemental form, bromine has an oxidation state of 0. However, when it forms the bromide ion (Br⁻) by gaining an electron, its oxidation state decreases from 0 to -1. This reduction in the oxidation state indicates that bromine is reduced.
In summary, the reaction between bromine and sodium forms the bromide ion (Br⁻), and bromine is reduced.
oxidized for freakin' sake
Becky halton for you first one (the b) go 4 down 6 over then you will see an 8. for the second one (the h) all i see is the lower case h's at the end it would rely hard to do if you added a uppercase i or lowercase L (had to do uppercase L to show you that it is not the uppercase i, if your going to do this next time make sure the L is lowercase =)
oxidized
Sodium forms the sodium ion (Na^+) and bromine forms the bromide ion (Br^-).
Since bromine (Br2, oxidation state of zero) goes to bromide ion (Br^-, oxidation state of -1), it is a gain of an electron for each bromide ion formed. Gain of electron is reduction. Obviously Na goes to Na^+, that is a loss of an electron, that is oxidation.
notice anything in this?:
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how about this?:
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