what is the balanced equation for thereaction of aluminum selenide with water including the physical states reactants and products
im given hydrogen selenide prepared by reacting aluminum selenide with water other product solid aluminum hydroxide
please can you help
minnie: donald: what next, goofy?
I will be happy to critique your work.
write the equation, starting with the formulas. THen balance it.
Very straightforward.
HI thanks
I get
Al2 Se3 + 6H2O ---> 2Al (oh)3 + 3H2Se
Is that correct because it looks right
HI thanks
I get
Al2 Se3 + 6H2O ---> 2Al (oh)3 + 3H2Se
Is that correct because it looks right
It looks ok to me except you should have used caps for the OH in Al(OH)3.
To balance the equation, you need to make sure that the number of atoms of each element is the same on both sides of the equation.
The balanced equation for the reaction of aluminum selenide with water is:
Al2Se3 (s) + 6H2O (l) → 2 Al(OH)3 (s) + 3H2Se (g)
Aluminum selenide (Al2Se3) is a solid (s) and water (H2O) is a liquid (l). Aluminum hydroxide (Al(OH)3) is a solid (s) and hydrogen selenide (H2Se) is a gas (g).
Remember, it is important to check that the equation is balanced by counting the number of atoms of each element on both sides of the equation. In this case, there are 2 aluminum (Al), 3 selenium (Se), 12 hydrogen (H), and 9 oxygen (O) atoms on both sides of the equation, making it balanced.