Chemistry

Calculate the solubility (in g/L) of calcium fluoride in water at 25°C if the Ksp for is 1.5 × 10-10 .

  1. 👍 0
  2. 👎 0
  3. 👁 705
  1. CaF2 <>Ca + 2 F

    let x represent solubility
    ksp=x*(2x)^2

    4x^3=Ksp
    solve for x, which is in moles per liter.

    now convert moles x to grams of CAF2 It should be on the order of .02grams/liter

    lets see
    solubility= x*molmass= cubrt(1.5E-10 /4)=.026grams/liter

    1. 👍 0
    2. 👎 1
    👨‍🏫
    bobpursley

Respond to this Question

First Name

Your Response

Similar Questions

  1. Chem 2

    what is the solubility of silver carbonate in water in 25 degrees celcius if Ksp=8.4X10-12? i don't know what to do Write the equation. Ag2CO3(s) ==> 2Ag^+ + CO3^= Ksp = (Ag^+2)(CO3^=) Let x = solubility of Ag2CO3. At

  2. chemistry

    what is the solubility of barium sulfate in a solution containing 0.050 M sodium selfate? The Ksp value for barium sulfate is 1.1E-10. An insoluble salt with formula MX3 has a solubility product constant written in terms of

  3. Chemistry

    Which of the following substances has the greatest solubility in water? A. Ca(OH)2, Ksp = 6.5 × 10-6 B. Ag2SO4, Ksp = 1.5 × 10-5 C. PbI2, Ksp = 7.9 × 10-9 D. Zn(IO3)2, Ksp = 3.9 × 10-6 E. BaF2, Ksp = 1.5 × 10-6

  4. Chem 2

    4) Calculate the solubility of calcium hydroxide, Ca(OH)2 (Ksp = 5.5 x 10-5) in grams per liter in: a. Pure water b. 0.10 M CaCl2

  1. Chemistry

    Calculate the molar solubility of Ag2SO4 when dissolved in water (Ksp = 1.8 x 10-5)

  2. chemistry

    Calculate the xolubility of calcium sulfate in 0.010 mol/L calcium nitrate at SATP CaSO4 ==> Ca^+2 + SO4^= Ca(NO2)2 ==> Ca^+2 + 2NO3^- = 0.01 M Ksp CaSO4 = (Ca^+2)(SO4^=) = ??. Look up Ksp for CaSO4. Subsitute 0.01 for Ca^+2 and x

  3. Chemistry

    Which of the following compounds has the greatest molar solubility? A) AgBr, Ksp= 5.4 x 10^13 B) Ba3(PO4)2, Ksp = 3.0 x 10^-23 C) Al(OH)3, Ksp = 1.9 x 10^-33 D) MgF2, Ksp = 7.4 x 10^-11 E) Pb(OH)2, Ksp = 1.2 x 10^-15 I know the

  4. CHEMISTRY

    The Ksp of (hydroxyapatite ) Ca5(PO4)3OH is 6.8 * 10^-37 , and its molar concentration is 2.7 * 10^-5 mol/L ,, if this (hydroxyapatite) reacts with fluoride , then the F- ions replace OH- ions and the product is Ca5(PO4)3F ,, if

  1. Chemistry

    A sample of calcium fluoride with a mass of 15.0 g contains 8.40 g of calcium. Assuming that the sample is pure calcium fluoride, how much calcium would be present in a 30.0 g sample? My answer: 16.8 g Ca Based on your answer and

  2. chemistry

    The solubility of PbF2 in water is 0.830 g/L. What is the value of Ksp? how would I calculate this?

  3. Chemistry

    what is the molar solubility of lead sulfate in 1.0 X 10^-3 M Na2SO4? The Solubility Product Constant PbSO4 Ksp= 1.8 x 10^-8 The Ksp expression is: Na2SO4 = [2Na][SO4^-2] [2Na]=2x [SO4^-2]=x Ksp= 1.8 x 10^-8 = (x)(2x) Ksp= 1.8 x

  4. Chemistry

    Calculate the solubility of ZnCO3 in .050 M Zn(NO3)2. Ksp= 3.0*10^-8 solubility= 1.7*10^-4

You can view more similar questions or ask a new question.