What volume, in ml, of a 60% of HCl acid solution must be added to 100 ml of a 30% HCl solution to make a 36% HCl solution.
We need 2 alegabreic (?) equations.
The first I can get is:
0.36x - 0.60y = 100ml (this is probably wrong)?
Blah. I can't get the other one. -.-
VolHCL*.60 + 100ml*.30 = (VolHCL +100ml).36
I don't see that you need a second.
To solve this problem, we can set up a system of equations based on the information given.
Let's assume that the volume of the 60% HCl acid solution to be added is represented by 'x' ml.
Equation 1: To mix the two solutions and obtain a 36% HCl solution, the total volume of the final solution will be (x + 100) ml.
Equation 2: The amount of HCl in the 60% acid solution (0.6x ml) plus the amount of HCl in the 30% acid solution (0.3 * 100 ml) should be equal to the amount of HCl in the final solution (0.36 * (x + 100) ml).
Using these two equations, we can solve for 'x'.
0.6x + 0.3 * 100 = 0.36 * (x + 100)
Simplify the equation:
0.6x + 30 = 0.36x + 36
Rearrange the equation:
0.6x - 0.36x = 36 - 30
0.24x = 6
Divide both sides by 0.24:
x = 6 / 0.24
x = 25
Therefore, 25 ml of the 60% HCl acid solution must be added to 100 ml of the 30% HCl solution to obtain a 36% HCl solution.