Question

Please help me to solve this Radical Expressions and equations word problem.

Here is the question:

Find the perimeter and the area of the rectangle.

Here are the measurements: length is (sqrt 6+2) and the width is (sqrt 6-2)

Answer 1

√6+2 + √6-2 = 2√6

(√6+2)(√6-2) = 6-2^2 = 2

Now do the math