Solve (16x^2)^-3/4
Please help using step by step. I don't understand how to do this. Thank you
first , because of the negatiave outer exponent
= 1/(16x^2)^3/4
since (ab)^x = a^x * a^x
we get
1/( (16^(3/4 ) * x^(3/2)
now 16^(3/4) = (16^(1/4) )^3 = 2^3 = 8
so finally
= 1/(8 (√x)^3 )