Algebra 2

Solving By Factoring:
The length of the side of a large square is 1 cm less than twice the length of the of the side of a smaller square. The area of the large square is 33cm^2 more than the area of the small square. Find the length of the sides of the two squares.

Please show work!!!

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  1. (2x-1)^2 = x^2 + 33
    4x^2-4x+1 = x^2+33
    3x^2-4x-32 = 0
    (3x+8)(x-4) = 0

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    posted by Steve

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