Complete the following reactions, where applicable. If no reaction occurs write N.R
A) blank + blank ---> Cu(NO3)2 + PbSO4
B) C6H12O6 + O2 --> blank + blank
C) AgNO3 + CuCI2 ---> blank + blank
A. Pb(NO3)2 + CuSO4 ==> ...
B. C6H12O6 + 6O2 --> 6CO2 + 6H2O
C. 2AgNO3 + CuCl2 ==> 2AgCl + Cu(NO3)2
A) To determine the products of the reaction, we need to combine the cations (positively charged ions) with the anions (negatively charged ions) in Cu(NO3)2 and PbSO4.
Cu(NO3)2 consists of the Cu^2+ cation (copper) and the NO3^- anion (nitrate).
PbSO4 consists of the Pb^2+ cation (lead) and the SO4^2- anion (sulfate).
To find the products, we switch the cations and anions between the compounds:
Cu(NO3)2 + PbSO4 ---> Pb(NO3)2 + CuSO4
This is the balanced equation for the reaction.
B) The reaction between C6H12O6 (glucose) and O2 (oxygen) is a combustion reaction. In a combustion reaction, glucose reacts with oxygen to produce carbon dioxide (CO2) and water (H2O).
The balanced equation for the combustion of glucose can be written as:
C6H12O6 + 6O2 ---> 6CO2 + 6H2O
This equation represents the complete combustion of glucose in the presence of excess oxygen.
C) To determine the products of the reaction between AgNO3 (silver nitrate) and CuCl2 (copper chloride), we need to combine the cations and anions.
AgNO3 consists of the Ag^+ cation (silver) and the NO3^- anion (nitrate).
CuCl2 consists of the Cu^2+ cation (copper) and the Cl^- anion (chloride).
When these compounds react, a double displacement reaction occurs. The cations and anions exchange partners:
AgNO3 + CuCl2 ---> AgCl + Cu(NO3)2
This is the balanced equation that represents the reaction between silver nitrate and copper chloride.