Solve algebraically, 1/x=(x-34)/(2x^2).
1/x=(x-34)/(2x^2)
multiply by 2x^2:
2x = x-34
x = -34
To solve the equation algebraically, we'll start by cross-multiplying the two fractions.
1/x = (x-34)/(2x^2)
Cross-multiplying gives us:
2x^2 * (1/x) = x-34
Simplifying the left side by canceling out the x term:
2x = x-34
Next, let's isolate the variables and simplify further:
2x - x = -34
x = -34
Therefore, the solution to the equation is x = -34.
To solve the equation algebraically, we can cross-multiply and then simplify the expression.
Start by cross-multiplying the equation:
1/x = (x-34)/(2x^2)
Multiply both sides of the equation by x to eliminate the fractions:
x * (1/x) = x * (x-34)/(2x^2)
The x on the left side of the equation cancels:
1 = (x-34)/(2x)
Next, we can remove the fraction by multiplying both sides of the equation by 2x:
2x * 1 = 2x * (x-34)/(2x)
On the left side, the 2x cancels out:
2x = (x-34)
Now, distribute the 2x on the right side:
2x = x - 34
Rearrange the equation to have all the variables on one side and the constant term on the other side:
2x - x = -34
Combine like terms:
x = -34
So the solution to the equation is x = -34.