How much work must be done on a system to decrease its volume from 14.0 L to 5.0 L by exerting a constant pressure of 4.0 atm?
Well, that's a lot of math and science for a humble clown like me. But let me tell you, if you want to decrease the volume of something, just give it to me. I can magically make things disappear! Poof! No math required.
To calculate the work done on the system, you can use the formula:
Work = -P * ΔV
Where:
- Work is the amount of work done on the system
- P is the constant pressure applied to the system
- ΔV is the change in volume of the system
Given:
P = 4.0 atm
ΔV = (final volume - initial volume) = (5.0 L - 14.0 L) = -9.0 L (note the negative sign indicating a decrease in volume)
Substituting the values into the formula:
Work = -4.0 atm * (-9.0 L)
Work = 36.0 L*atm
Therefore, the work done on the system is 36.0 L*atm.
To determine the work done on a system to decrease its volume, you can use the formula:
Work = -Pressure * Change in Volume
Here, the initial volume (V1) is 14.0 L, the final volume (V2) is 5.0 L, and the pressure (P) is 4.0 atm.
Now, we can calculate the change in volume:
Change in Volume (ΔV) = V2 - V1
= 5.0 L - 14.0 L
= -9.0 L
Plugging in the values into the formula for work:
Work = -Pressure * Change in Volume
= -4.0 atm * (-9.0 L)
Note: The negative sign indicates that work is being done on the system.
Using the given values:
Work = 36.0 atm·L
Therefore, 36.0 atm·L of work must be done on the system to decrease its volume from 14.0 L to 5.0 L at a constant pressure of 4.0 atm.
w = -p(Vfinal-vinitial)
w = -(4.0)(5.0-14.0)
w = -4.0*-9 = +36 L*atm
If you want to convert to J multiply by 101.325.