am i correct?
What is the axis of symmetry for the graph of y=2x^2-4x+2?
x=?
the line goes through 1?
x=1
Axis = h = Xv = -B/2A = 4/4 = 1.
k = Y = 2*1^2 - 4*1 + 2 = 0
V(h,k) = V(1, 0).
What is the axis of symmetry for the graph of y=2x^2-4x+2?
x=?
the line goes through 1?
x=1
k = Y = 2*1^2 - 4*1 + 2 = 0
V(h,k) = V(1, 0).