How many oxygen atoms are in 0.07 mol of dinitrogen pentoxide (N2O5)? Answer in units of atoms
There are 6.02E23 molecules in 1 mol so there are 0.07 x 6.02E23 molecules in 0.07 mols. Since there are 5 O atoms in 1 molecule of N2O5, # O atoms will be 5x the number of molecules N2O5.
Well, first off, let's give a round of applause for dinitrogen pentoxide for having such a fancy name! Now, let's do some chemistry math. One molecule of dinitrogen pentoxide (N2O5) contains 5 oxygen atoms.
In 0.07 mol of dinitrogen pentoxide, we need to multiply the number of oxygen atoms in one molecule (5) by Avogadro's number, which is approximately 6.022 x 10^23 atoms/mol.
So, 0.07 mol of dinitrogen pentoxide would contain approximately 0.07 x 5 x 6.022 x 10^23 oxygen atoms.
Voilà! The answer, my friend, is 2.1134 x 10^23 oxygen atoms. That's quite a mouthful, isn't it?
To find the number of oxygen atoms in 0.07 mol of dinitrogen pentoxide (N2O5), we need to multiply the Avogadro's number (6.022 x 10^23 atoms/mol) by the number of moles.
Number of oxygen atoms = 0.07 mol x (6.022 x 10^23 atoms/mol)
Calculating this, we get:
Number of oxygen atoms = 4.2154 x 10^22 atoms
Therefore, there are approximately 4.2154 x 10^22 oxygen atoms in 0.07 mol of dinitrogen pentoxide (N2O5).
To find the number of oxygen atoms in 0.07 mol of dinitrogen pentoxide (N2O5), you need to use Avogadro's number and the chemical formula of dinitrogen pentoxide.
Avogadro's number, which is approximately equal to 6.022 x 10^23, represents the number of particles (atoms, molecules, etc.) per mole. Therefore, 1 mol of any substance contains 6.022 x 10^23 individual particles.
The chemical formula of dinitrogen pentoxide (N2O5) tells us that there are two nitrogen atoms (N) and five oxygen atoms (O) in each molecule of dinitrogen pentoxide.
To determine the number of oxygen atoms, we can multiply the number of moles of dinitrogen pentoxide by the number of oxygen atoms per molecule of dinitrogen pentoxide.
Number of oxygen atoms = (Number of moles of dinitrogen pentoxide) x (Oxygen atoms per molecule)
Number of oxygen atoms = 0.07 mol x (5 oxygen atoms/molecule)
Number of oxygen atoms = 0.35 mol
Finally, we convert the number of moles to atoms using Avogadro's number:
Number of oxygen atoms = (0.35 mol) x (6.022 x 10^23 atoms/mol)
Number of oxygen atoms = 2.1117 x 10^23 atoms
Therefore, there are approximately 2.1117 x 10^23 oxygen atoms in 0.07 mol of dinitrogen pentoxide (N2O5).