1. t + 27 = 21
t = –6
t = 47
t = 6
t = –47
2. 24 = m – 32
m = –8
m = 56
m = 768
m = –56
3. Tamara has eaten 1,400 calories for breakfast and lunch. She has 800 more calories, c, that she can eat for dinner.
Write and solve an equation to find Tamara’s daily caloric intake.
1,400 – 800 = c; c = 600
1,400 + 800 = c; c = 2,200
1,400 – c = 800; c = 2,200
1,400 + 800 = c; c = 600
4. Steven’s old cell phone cost $125.00 less than his new phone. His old cell phone cost $155.00.
Write and solve an equation to find the cost of Steven’s new cell phone.
n – 125 = 155; n = $30
155 – 125 = n; n = $30
125 + n = 155; n = $280
n – 125 = 155; n = $280
What are your answers?
What do you think the answers are first?
I like to think of these as money.
Imagine the first one there is you had €27 in your hand, something happened to it and now you have €21. So, what happened? Was money added or taken away? How much was added or taken away?
1. To solve the equation t + 27 = 21, we need to isolate the variable t. To do this, we subtract 27 from both sides of the equation:
t + 27 - 27 = 21 - 27
t = -6
Therefore, t = -6 is the value of the variable that satisfies the equation.
2. To solve the equation 24 = m - 32, we need to isolate the variable m. To do this, we add 32 to both sides of the equation:
24 + 32 = m - 32 + 32
56 = m
Therefore, m = 56 is the value of the variable that satisfies the equation.
3. To find Tamara's daily caloric intake, we need to add the calories she has eaten for breakfast and lunch to the calories she can eat for dinner. So, the equation is:
1400 + c = 1400 + 800
c = 2200
Therefore, c = 2200 is the value of the variable that represents Tamara's daily caloric intake.
4. To find the cost of Steven's new cell phone, we need to determine the cost of his old cell phone and subtract $125.00. So, the equation is:
n - 125 = 155
n = 280
Therefore, n = $280 is the cost of Steven's new cell phone.