Math

The Hotel Regal has 600 rooms. Currently the hotel is filled . The daily rental is \$ 250 per room.
For every \$ 4 increase in rent the demand for rooms decreases by 4 rooms.
Let x = the number of \$ 4 increases that can be made.
What should x be so as to maximize the revenue of the hotel ?
What is the rent per room when the revenue is maximized? \$
What is the maximum revenue? \$

1. r(x) = (600-4x)(250+4x)

Now plug and chug.

posted by Steve

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