# Chemistry

The dimensions of aluminum foil in a box for sale at a supermarket are 66.6 yards by 12 inches. The mass of the foil is .83kg. What is the thickness of the foil (in cm)?
(1in = 2.54 cm)

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1. 66.6 yards x (3 feet/yd) x (12 in/foot) x (2.54 cm/in) = length in cm
12 inches wide x (2.54 cm/inch) = width in cm

mass = volume x density or volume = mass/density = 830g/look up density
solve for volume in cc.

Then volume = length x width x thickness
You know v, l, w, and you solve for thickness (in cm)

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2. density=mass/volume=mass/LWT

T=mass/(L*W*density)

change yards to cm, inches to cm first. density should be in grams/cm^3, change kg to grams...

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bobpursley
3. 66.6 yards * 36 in/yard * 2.54 cm/in = L

12 in * 2.54 cm /in = w

volume = w * L * t

so
2.7 grams/cm^3 * w * L * t = 830 grams

solve for t

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4. Thankyou all so much for your help

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5. You are welcome.

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6. length= 6089.9cm
width=30.48cm
volume= 307g

307g = 6089.9cm X 30.48cm X thickness

thickness= .00165 cm

was the information I got correct?

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7. I agree with that.

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