How do you write the equation of the line with slope -2 that passes through the point (-1, -3) in slope-intercept form?
Thanks to anyone that helps! :)
To write the equation of a line in slope-intercept form (y = mx + b), you need to know the slope (m) and the y-intercept (b).
In this case, you have been given the slope of the line, which is -2, and a point that the line passes through, which is (-1, -3).
To find the equation, you can follow these steps:
Step 1: Use the point-slope form of a line to find the equation.
The point-slope form is given by the equation: y - y1 = m(x - x1), where (x1, y1) is the given point on the line.
Let's plug in the given values into the equation:
y - (-3) = -2(x - (-1))
Simplifying the negative signs:
y + 3 = -2(x + 1)
Step 2: Convert the equation into slope-intercept form.
To do this, we need to simplify the equation and isolate y on one side.
Start by distributing the -2 to the terms inside the parentheses:
y + 3 = -2x - 2
Next, subtract 3 from both sides of the equation to isolate y:
y = -2x - 2 - 3
Simplifying further:
y = -2x - 5
Now, the equation of the line with slope -2 that passes through the point (-1, -3) is y = -2x - 5, written in slope-intercept form.