math

solving equation (b-c)x² + (c-a)x + (a-b) = 0 folling roots are obtained

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asked by Nithin
  1. Just use the quadratic formula:

    x = (-(c-a)±√((c-a)^2 - 4(b-c)(a-b)))/(2(b-c))

    You can play around with that some, but I don't see much in the way of simplification.

    http://www.wolframalpha.com/input/?i=%28b-c%29x%C2%B2+%2B+%28c-a%29x+%2B+%28a-b%29

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    posted by Steve

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