physics

Cars A and B are racing each other along the same straight road in the following manner: Car A has a head start and is a distance DA beyond the starting line at t=0. The starting line is at x=0. Car A travels at a constant speed vA. Car B starts at the starting line but has a better engine than Car A, and thus Car B travels at a constant speed vB, which is greater than vA.


How long after Car B started the race will Car B catch up with Car A?
Express the time in terms of given quantities.


How far from Car B's starting line will the cars be when Car B passes Car A?
Express your answer in terms of known quantities. (You may use tcatch as well.)

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  1. ok, when they meet.
    finalpositionB=x =vB*time
    final poistionA=x+DB=vA*time+DB

    setting these final positions equal
    vA*time+DB=vB*time
    time=DB/(vB-Va)

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