At some temperature,the reaction
PCl3(g) +Cl2(g) ====PCl5(g)
is at equilibrium when the concentration of PCl3, Cl2, and PCl5 are 10, 9.0, and 12mol/L, respectively. Calculate the value of Kc for this reaction at that temperature.
What's your problem here? You substitute the concn listed into the Kc expression and solve for Kc.
okiee thanks
To calculate the value of Kc for the reaction, you'll need to use the given equilibrium concentrations of the reactants and products. Kc represents the equilibrium constant in terms of concentrations.
The equation for Kc is defined as follows:
Kc = [PCl5] / ([PCl3] * [Cl2])
In this case, the equilibrium concentrations are given as follows:
[PCl3] = 10 mol/L
[Cl2] = 9.0 mol/L
[PCl5] = 12 mol/L
Now, substitute the values into the equation:
Kc = [12] / ([10] * [9.0])
Simplify the equation:
Kc = 12 / (10 * 9.0)
Kc = 12 / 90
Kc = 0.1333
Therefore, the value of Kc for this reaction at that temperature is 0.1333.