solve trinomial

x^2-3x+4

nothing to solve. However, if you meant

x^2-3x+4 = 0, the two complex values of x that make it true are

3/2 ± √7/2 i

If you meant to type

x^2-3x-4 = 0, then that factors to
(x-4)(x+1) = 0

and it should be clear which values of x are solutions there.