can someone help me with this word problem?
if a pro basketball player has a vertical leap of about 20 inches, what is his hangtime?
It is twice the time that it would take an object to fall 20 inches.
hangtime T = 2 * sqrt(2H/g)
H = 20"/(12 in/ft) = 1.6667 ft
g = 32.2 ft/s^2
T = 0.64 s
Of course, I can help you with that! To calculate the hangtime of a basketball player, we need to use the formula:
hangtime = (2 * vertical leap) / gravity
1. The gravity value we'll use is approximately 9.8 meters per second squared (this is the average acceleration due to gravity on Earth).
2. First, we need to convert the vertical leap from inches to meters. Since 1 inch is approximately 0.0254 meters, we'll multiply 20 inches by 0.0254 to get the leap value in meters.
3. Now we have all the values we need, so we can plug them into the formula: hangtime = (2 * leap) / gravity.
Let's perform the calculations step by step:
- Convert the vertical leap from inches to meters: 20 inches * 0.0254 meters/inch = 0.508 meters.
- Now, plug in the values into the formula: hangtime = (2 * 0.508) / 9.8.
- Finally, calculate the hangtime: hangtime ≈ 0.103 seconds.
Therefore, the estimated hangtime of the basketball player is approximately 0.103 seconds.