physics-please help

A proton, traveling with a velocity of 6.8 × 106 m/s due east, experiences a magnetic force that has a maximum magnitude of 8.6 × 10-14 N and direction of due south. What are the magnitude and direction of the magnetic field causing the force? If the field is up, then enter a number greater than zero. If the field is down, then enter a number less than zero

asked by Sara
  1. Bqv=6.8 × 106*8.6 × 10-14 *1.6E-19

    posted by bobpursley
  2. is the answer in T? I had 9.3568E-26 and it says the answer is wrong

    posted by Sara
  3. you are looking for B, so the equation would be

    B= F/qv

    posted by tfish

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