A proton, traveling with a velocity of 6.8 × 106 m/s due east, experiences a magnetic force that has a maximum magnitude of 8.6 × 10-14 N and direction of due south. What are the magnitude and direction of the magnetic field causing the force? If the field is up, then enter a number greater than zero. If the field is down, then enter a number less than zero

1. Bqv=6.8 × 106*8.6 × 10-14 *1.6E-19

posted by bobpursley

posted by Sara
3. you are looking for B, so the equation would be

B= F/qv

posted by tfish

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