The useful energy output of an engine is 1.50 × 103 kJ and the total mechanical energy input is 4.32 x 103 kJ . The efficiency of the engine is __________%
assume you mean 10^3
100 ( 1.50/ 4.32 )
To find the efficiency of the engine, we need to use the following formula:
Efficiency (%) = (Useful Energy Output / Total Energy Input) x 100
Given that the useful energy output is 1.50 × 10^3 kJ and the total mechanical energy input is 4.32 × 10^3 kJ, we can substitute these values into the formula:
Efficiency (%) = (1.50 × 10^3 / 4.32 × 10^3) x 100
Now, let's simplify the expression:
Efficiency (%) = (0.347) x 100
Efficiency (%) = 34.7%
Therefore, the efficiency of the engine is 34.7%.