Question

250 gms of Zn (65.5) gave 242 gms of ZnO on ignition. Calculate %age yield of the reaction.

Answer 1

2Zn + O2 ==> 2ZnO

mols Zn = grams/molar mass = ?
Convert mols Zn to mols ZnO
Then g ZnO = mols ZnO x molar mass ZnO. This is the theoretical yield (TY). The actual yield (AY) is 242.
%yield = (AY/TY)*100 = ?