How much heat must be added to 128.7 g of ice at 0 degrees Celsius to melt the ice completely?
Answer = _____calories
Heat=mass*HeatFusion
look up the heat of fusion for water at 0C in calories/gram (I recommend you memorize that one).
To determine the amount of heat required to melt the ice completely, we need to consider the specific heat of ice and the heat of fusion.
Here are the steps to calculate the answer:
1. Calculate the heat required to raise the temperature of the ice from 0 degrees Celsius to its melting point:
Heat = mass × specific heat × change in temperature
The specific heat of ice is approximately 0.5 calories/gram·°C.
The mass of ice is given as 128.7 g.
The initial temperature is 0°C, and the final temperature is 0°C (the melting point).
Heat = 128.7 g × 0.5 cal/(g·°C) × (0°C - 0°C) = 0 calories
Since the temperature does not change during a phase change, no heat is needed to raise the temperature from 0°C to 0°C.
2. Calculate the heat required for the phase change (melting):
Heat = mass × heat of fusion
The heat of fusion for ice is approximately 79.7 calories/gram.
Heat = 128.7 g × 79.7 cal/g = 10257.39 calories
Therefore, the amount of heat required to melt the ice completely is approximately 10257.39 calories.