Physics

A proton with mass 1.67×10−27 kg and charge 1.60×10−19 C accelerates from rest in a uniform electric field of strength 500 N/C. (a) What is the magnitude of the acceleration of the proton? (b) How long does it take the proton to reach a speed of 35,000 m/s? (c) What distance has the proton traveled when it reaches this speed? (d) What is the kinetic energy of the proton at 35,000 m/s?

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  1. I have the 1st two answers, I just don't know how to calculate the other two. Everything I have tried comes out with a wrong answer.

      (a) 479.04e+8 m/s2
      (b) 7.30627923e-7  s
      (c)   m
      (d)   J

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  2. F = q E = m a
    so
    a = (q/m)E
    = (1.6*10^-19/1.67*10^-27)5*10^2
    = 4.79 * 10^10 m/s^2

    v = a t
    3.5*10^4 = 4.79 * 10^10 t
    t = .731 * 10^-6 = 7.31*10^-7 seconds

    d = (1/2) a t^2

    Ke = (1/2) m v^2

    I think you can do c and d

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  3. I don't understand what the "^2" means or how to use it in the equation.

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  4. The ^2 means squared. v^2 is velocity squared.

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    bobpursley
  5. what would be the mass of the proton?

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