A man moves on his bike with 54km/h and takes u- tune (180 degree)and continues it speed to move with same speed .the time of u-tune is 10sec.find its average accleration
r = 54km/h = 54000m/3600s = 15m/s.
a = (V-Vo)/t = (-15-15)/10 = -30/10=-3.0
m/s^2.
To find the average acceleration of the man during the U-turn, we need to first calculate the change in velocity and then divide it by the time taken.
Given:
Initial velocity (v1) = 54 km/h
Final velocity (v2) = -54 km/h (since the man changes direction during the U-turn)
To calculate the change in velocity, we can subtract the final velocity from the initial velocity:
Change in velocity (Δv) = v2 - v1
= (-54 km/h) - (54 km/h)
= -108 km/h
Now, we need to convert the change in velocity to the SI unit of meters per second (m/s). To do this, we can use the conversion factor: 1 km/h = 1000 m/3600 s.
Change in velocity (Δv) = -108 km/h × (1000 m/3600 s)
= -30 m/s
Next, we divide the change in velocity by the time taken to perform the U-turn to find the average acceleration:
Average acceleration (a) = Δv / t
= (-30 m/s) / 10 s
= -3 m/s²
Therefore, the average acceleration of the man during the U-turn is -3 m/s². The negative sign indicates that the acceleration is in the opposite direction to the initial velocity.