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How many gram ofsodiun fluoride should be added to 100000liter of drinking water containing 0.6 ppm of sodium fluoride to provide a recommended concentration of 1.75 ppm

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asked by sara
  1. look at the amounts of NaF involved:
    (.6/10^6)*100000 + 1.0*x = (1.75/10^6)(100000+x)
    x = 0.115

    check:
    .6 ppm in 10^5L = 0.06g
    add 0.115 g and you have 0.175g, or 1.75ppm

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    posted by Steve
  2. Thank you .. but the right answer in my book is 115g

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    posted by sara
  3. Hmm. Obviously I misplaced a decimal point. I expect you can find the flaw in my reasoning.

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    posted by Steve
  4. 1.75-0.6ppm=1.15ppm
    Which means 1.15g in 10^6mls
    So how many grams in 10litres.
    Change litres into mls and calculate
    Answer will be 115g

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