chem

how many NaOH are needed to to react with 98.1 mol AlO3

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asked by marie
  1. Dear marie,
    I guess there is no AlO3 existing
    So do you actually mean aluminium oxide
    (Al2O3)
    The balanced equation is
    3OH- + AL3+ -------> Al(OH)3
    mol of aluminium oxide needed= 98.1

    as 1 mole of aluminium oxide required 3 moles of sodium hydroxide to react with

    mol of sodium hydroxide= 98.1X3
    = 294.3

    number of grams of NaOH needed=
    294.3x( 23+ 16 +1)
    =11772grams

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    posted by Barry

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