intro to chem

A 45kg sample of water absorbs 367kJ of heat. If the water was initially 24.8ºC, what is final temperature? Please explain steps. Thanks

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asked by Carol
  1. heat=mass*c*(tf-ti)
    steps? You know heat, mass, ti. The only issue is the specific heat of water UNITS. YOu need c in kJ/kgC

  2. mass of water= 367,000 x specific heat (24.8?) x Tf (how do i find this? what part of the question tells me?)

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    posted by carol
  3. Lord:
    mass water=45kg
    heat=367kJ
    c= 4.17kJ/kgC
    Ti=24.8C

    367kJ=45kg*4.17kJ/kgC*(Tf-20)

    Tf-20=367/(45*4.17)
    Tf=367/(45*4.17) +20

  4. I don't appreciate the LORD: if Jesus had anything to do with it I would NOT have to take chemistry!

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    posted by carol
  5. where did you find the C?

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    posted by Jack

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