math

find the height in feet of a ball after 6 seconds in the air. after one second the ball is 148 feet in the air; after 2 seconds it is 272 feet in the air

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asked by TERESA
  1. The height y(t) is given by
    y(t) = h + vt - 16t^2
    h + v - 16 = 148
    h + 2v - 64 = 272
    So,
    h=-8
    v=172

    y(t) = -8 + 172t - 16t^2
    y(6) = 448

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    posted by Steve
  2. You divide by 6 afterwards ??

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