# math

Find the reason for the geometric progression in which a1 = 1, n = 3, S3 = 157

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1. S3 = 1(1-r^3)/(1-r) = 157
1+r+r^2 = 157
r^2+r-156 = 0
(r-12)(r+13) = 0
r = 12 or -13
So, the GPs are

1,12,144,...
1,-13,169,...

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posted by Steve

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