How can just adding one or subtracting one make the difference? I did the first one but can't come up with the second one. The first equation is:
x = 4y + 1 Subtract 1 from both sides
x - 1 = 4y Now divide both sides by 4
(x/4) - (1/4) = y
My slope is (¼) and my y-intercept is (-¼) What is it for the second equation?
Where is the second equation ?
Sorry,
x = 4y – 1
To find the second equation, we need to understand the relationship between the first equation and the second equation.
In the first equation, we started with "x = 4y + 1" and subtracted 1 from both sides to isolate the term with "x". This allowed us to rewrite the equation in the form of "x - 1 = 4y".
To find the second equation, we can similarly start with the equation "x - 1 = 4y" and add 1 to both sides. Adding 1 to both sides allows us to isolate the term with "x", just like subtracting 1 did in the first equation.
Here's how it looks:
Starting with:
x - 1 = 4y
Adding 1 to both sides:
x - 1 + 1 = 4y + 1
x = 4y + 2
Therefore, the second equation is "x = 4y + 2".
Now, to determine the slope and y-intercept of the second equation, we need to rewrite the equation in slope-intercept form, which is "y = mx + b".
In this equation, "m" represents the slope and "b" represents the y-intercept.
Let's rewrite the second equation in slope-intercept form:
x = 4y + 2 Move the term with "x" to the other side
4y = x - 2 Divide all terms by 4
y = (1/4)x - (1/2)
So, the slope of the second equation is 1/4, and the y-intercept is -1/2.