Algebra 1--Please, help me!

Mulitply ((n-5)/(n^2 - 2n -3)) / ((n-3)/(n^2 -4n - 5)).

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  1. ((n-5)/(n^2 - 2n -3)) / ((n-3)/(n^2 -4n - 5))
    multiply both sides by (n^2 - 2n -3)(n^2 - 4n - 5) , sometimes called cross-multiplying

    n^3 - 4n^2 - 5n - 2n^2+ 8n + 10 = n^3 - 2n^2 - 3n - 3n^2 + 6n + 9
    -n^2 = -1
    n^2 = 1
    n = ± 1

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    posted by Reiny

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