# algebra

Solve the equations by finding the exact solution.
a 3= x -3 what is x
b In e = In like a check mark 7 with a 6 under the 7 -3 In e x is what

Thank you very much for your time

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1. 3 = x-3
6 = x

As for the other, I can't quite decode your weird text. I can say that

ln e = 1
ln √n = 1/2 ln n
ln a - ln b = ln(a/b)

If you have

ln e = ln √6 - 3ln x
1 = ln√6 - ln x^3
1 = ln √(6/x^6)
e = √(6/x^6)
6/x^6 = e^2
x^6 = 6/e^2
x = (6/e^2)^(1/6)

I suspect that is not what you were after, but it should show you how to manipulate logs a little.

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posted by Steve
2. thank you Steve it does give me a direction in which to guide me.

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