# math

1/a+1/b+1/c=2/1
c¡Ùb¡Ùa
find a£¿b£¿c's Positive integer solution

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1. 1/a + 1/b + 1/c = 2
If we let a <= b <= c, then there's always the easy case where
a=1 b=2 c=2

I guess that's the only one, since if any of the three values is 3 or more, then the fractions can't add up to 2.

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posted by Steve

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