math

Use the binomialsl theorem to find the binomial binomialsion of the expression

(x-3)^5

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asked by Kim
  1. for n = 5
    coefs are

    1 5 10 10 5 1
    for example
    C(5,3) = 5!/[ 3!(5-3)!] = 5*4/2 = 10

    so
    1 x^5 + 5 x^4(-3) +10 x^3(-3)^2 +10x^2(-3)^3 +5x(-3)^4 +1 (-3)^5

    = x^5 -15x^4+90x^3-270x^2+405x-243

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    posted by Damon

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