MATH

Two Planes leave an airport at the same time, one flying 300km/h and the other at 420km/h
The angle between their flight paths is 75 degrees after three hours, how apart are they?
answer:
so it would be c^2=a^2+b^2-2ab cos C
900^2+1260^2-2(900)(1260)(cos75)
c^2=33542.9
c=183.14km
is it right?

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  1. c^2 = 900^2+1260^2-2(900)(1260)(cos75) correct
    = 810,000 + 1,587,600 - 587,001.59
    = 1,810,598.4 (you had 33542.9)
    c = √1,810,598.4
    c = 1345.58

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