# Physics

Peter is shooting arrows at a target with a bow. The target is 10m above the arrows launch point and some distance from Peter. If the arrows are shot with initial velocity Vo at 60 degrees with respect to the ground, then they will hit the target at the highest point of their trajectory. Find the initial speed of the arrows.

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1. Y^2 = Y0^2 + 2g*h
Yo^2 = Y^2-2g*h = 0 + 19.6*10 = 196
Yo = 14 m/s = Ver. component of initial
velocity.

Yo = Vo*sin60 = 14 m/s.
Vo = 14/sin60 = 16.2m/s[60o]

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posted by Henry

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