21x^3+67x^2-36=0 solutins

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asked by ANNA
  1. tried: ±1, ±2, ±3
    success at x = -3

    by synthetic division
    21x^3+67x^2-36=(x+3)(21x^2+ 4x - 12)
    = (x+3)(3x-2)(7x+6)

    so what do you think?

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    posted by Reiny

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