Please help me solve and find the excluded values for this problem. Also please show me the work for this problem I want to learn!F(h) = x^2-9/x^2-4x+3
division by zero is not defined. So, when the denominator is zero, f(x) is not defined.
x^2-4x+3 = (x-1)(x-3)
so, when x=1 or 3, you are trying to divide by zero. Those values are not part of the domain.
Note that x^2-9 = (x-3)(x+3)
So, for any value except x=3, f(x) = (x+3)/(x-1)
The graph available below should help you explore other properties of f(x).
http://www.wolframalpha.com/input/?i=%28x^2-9%29%2F%28x^2-4x%2B3%29posted by Steve