# Algebra 2

Please help me solve and find the excluded values for this problem. Also please show me the work for this problem I want to learn!F(h) = x^2-9/x^2-4x+3

1. division by zero is not defined. So, when the denominator is zero, f(x) is not defined.

x^2-4x+3 = (x-1)(x-3)

so, when x=1 or 3, you are trying to divide by zero. Those values are not part of the domain.

Note that x^2-9 = (x-3)(x+3)

So, for any value except x=3, f(x) = (x+3)/(x-1)

The graph available below should help you explore other properties of f(x).

http://www.wolframalpha.com/input/?i=%28x^2-9%29%2F%28x^2-4x%2B3%29

posted by Steve

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