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Algebra
What is the vertex form of the equation? y = x^2+12x4 My work: (x^2 + 12x)4 (x^2 + 12x + 36)4 + 36 Y= (x+36)^2 + 32 Is this correct? I am not sure if I did this right or not? Thank you!
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5x 3 = 11 + 12x combine like figures add 3 to both sides to remove the 3 5x= 14+ 12x Now I get confused. If I remove the 12x I have to subtract 12x from 5x which gives me an answer of 7x=14 would the correct answer thus be x=
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Evaluate a/b+c^d for a=6,b=3,c=4 and d=5 A.42*** B.18 C.82 D.360 What is the simplified form of the expression ? (12x8y) A.12x+8y B.12x8y***** C.12x+8y D.12x8y
asked by Help please on September 3, 2015 
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1/3  5/6 = 1/X SOLVE 1/3  5/6 = 1/X Let's remove the denominators by multiplying by 12X 12X*(1/3)  12X*(5/6) = 12X*(1/X) Clear the fractions. 4X  10X = 12 6X=12 multipy by 1 6X=12 Divide both sides by 6 6X/6 = 12/6 X = 2
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Simplify the polynomial [(6x8)2x][(12x7)(4x5)]. I came up with two answers: 36x^2  72x + 35 or 12x^2 + 8x  2 Are either one of these the correct answer?
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What is dy/dx of y=12/12Xy^3 ???? Any idea anyone??? y=12/12Xy^3 I assume you mean... y=12/(12Xy^3) 12Xyy^4=12 12x dy/dx + 12y 4y^3 dy/dx=0 dy/dx (12x 4y^3)=12y solve for dy/dx
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asked by Mai on January 29, 2018 
bobpursly,
Is this correct now after i revised it Multiply. 3xy^2(5xy4x+6y) 3xy^2(5xy)=15x^2y^3 3xy^2(4x)=12x^2y^2 3xy^2(6y)=18xy^3 so i get from this 15x^2y^312x^2y^2+18xy^3 correct awsome i just thought that the 15x^2y^312x^2y^2
asked by jas20 on February 28, 2007 
algebra1
could you walkthrough the steps to solving this problem because I am stuck; 3x5(3x7)=2(x+9)+45 Let me know if you have a question in any step. 3x5(3x7)=2(x+9)+45 3x15x+35= 2x+18+45 12x+35 = 2x+63 35 35 12x= 2x +6335
asked by unknown on March 21, 2007