How much heat (in Joules) is gained by the water when a chemical reaction takes place in 100.0 ml aqueous solution, has a temperature increase of 10.20°C and a specific heat capacity of 4.180 J/°Cg? [Hint: ignore any effects of the calorimeter and solve for qwater]
qwater = mass H2O x specific heat H2O x (Tfinal-Tinitial)
Note: Tfinal-Tinitial = delta T = 10.20 C.
To find the amount of heat gained by the water, we can use the formula:
q = mcΔT
where:
q is the heat gained
m is the mass of the water
c is the specific heat capacity of water
ΔT is the change in temperature
In this case, we have the following information:
m = 100.0 ml (or 100.0 g, since the density of water is 1 g/ml)
c = 4.180 J/°Cg
ΔT = 10.20°C
Now, plug the values into the formula:
q = (100.0 g) * (4.180 J/°Cg) * (10.20°C)
Simplifying the equation:
q = 4180 J/°C * 10.20°C
q = 42,636 J
Therefore, the water gains 42,636 Joules of heat.