Physics

A 10kg block is attached to a massless cord that doesn't stretch or sag which is rapped around a disc like wheel, m=5Kg, I= (1/2)mR^2. If the block is allowed to drop straight down held back only by the rotation of the wheel:

1. What is the tension of the rope?
2. What is the acceleration of the block?

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  1. The force on the rope is tension, which is equal to mg-ma

    But this same tension is spinning the wheel:

    angularacceleration=Tension/I
    a/R=Tension/I

    aI=R(mg-ma)
    solve for a, then you have it.

    check my thinking.

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    bobpursley

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