The nucleus of a copper atom contains 29 protons and has a radius of 4.8*10^-15m. How much work (in electron volts) is done by the electric force as a proton is brought from infinity, where it is at rest, to the "surface" of a copper nucleus?

I really got no clue to do it. Can anyone please explain and help????THANKS A LOT!!!!

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  1. I would assume the protons are equally distributed in the nucleus. From that, you can get E at the surface,and E(r) outside the nucleus

    Work= INT Eqdr Where E is a function of r.

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  2. i still don't really get it...Can you tell me more about it?

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