A red ball of mass 0,6 kg,travelling at 5 m.s^-1 on a frictionless surface ,stikes a stationary green ball of mass 0,3 kg.after the collision,the red ball continues to move in its original direction at 2m.s^-1,while the green ball moves in front of the red ball.
Determine the velocity of the green ball.
To determine the velocity of the green ball, we can use the principles of conservation of momentum.
The principle of conservation of momentum states that the total momentum of an isolated system remains constant before and after a collision. In this case, the system consists of the red ball and the green ball.
Before the collision, the momentum of the system is given by:
Momentum(red ball) = mass(red ball) * velocity(red ball) = 0.6 kg * 5 m/s = 3 kg·m/s.
Since the green ball is stationary, its initial velocity is 0 m/s, and thus its initial momentum is:
Momentum(green ball) = mass(green ball) * velocity(green ball) = 0.3 kg * 0 m/s = 0 kg·m/s.
After the collision, the red ball continues to move at 2 m/s, and the green ball moves in front of the red ball. Let's denote the velocity of the green ball as Vg.
Therefore, the final momentum of the system is:
Momentum(red ball) = mass(red ball) * velocity(red ball) = 0.6 kg * 2 m/s = 1.2 kg·m/s.
Momentum(green ball) = mass(green ball) * velocity(green ball) = 0.3 kg * Vg.
According to the principle of conservation of momentum, the total momentum before the collision must be equal to the total momentum after the collision. So, we can set up the following equation:
Initial momentum + Initial momentum = Final momentum + Final momentum
0 kg·m/s + 3 kg·m/s = 1.2 kg·m/s + 0.3 kg * Vg
Simplifying the equation, we get:
3 kg·m/s = 1.2 kg·m/s + 0.3 kg * Vg
Now, we can solve for Vg:
0.3 kg * Vg = 3 kg·m/s - 1.2 kg·m/s
0.3 kg * Vg = 1.8 kg·m/s
Vg = 1.8 kg·m/s / 0.3 kg
Vg = 6 m/s
Therefore, the velocity of the green ball after the collision is 6 m/s.