I have a triangle with sides measuring x^3 + 1, x^3 - 1, and x - 1. I'm asked to find its perimeter. Is the triangle's perimeter 2x^3 + x - 1?
correct
PERIMETER IS ADDING ALL ROUND EXCEPT A RECTANGLE WHERE YOU COULD USE P=2(L+B).
HENCE; X^3+1+X^3-1+X-1=2X^6-1
To find the perimeter of a triangle, you need to sum up the lengths of all its sides.
In this case, the lengths of the sides are x^3 + 1, x^3 - 1, and x - 1.
To find the perimeter, you need to add these three lengths together:
Perimeter = (x^3 + 1) + (x^3 - 1) + (x - 1)
Simplifying this expression, we have:
Perimeter = x^3 + x^3 + x - 1 + 1 - 1
Perimeter = 2x^3 + x - 1
So, the triangle's perimeter is indeed 2x^3 + x - 1.