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a silver bar 0.125 meter long is subjected to a temperature change from 2oo degrees celsius to 100 degrees Celsius what will the length of the bar be after the temperature change

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asked by Alice
  1. L = Lo + a/oC(T-To)*Lo
    L = 0.125 + 1.9*10^-6(100-200)0.125 =
    0.124976

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    posted by Henry

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